The first building block of a warped linear prediction filter is a first-order all-pass filter. Let's begin with its transfer function ([1]):
$$D(z) = \frac{z^{-1} - \lambda}{1 - \lambda z^{-1}}$$By setting λ = 0, this reduces to a unit delay:
$$D(z) = z^{-1}$$Unit delay, i.e. multiplying by z-1 in the z-domain, implies a lag of 1 sample in the discrete time domain ([2]): $$y[n] = D(z)x[n] \implies y[n] = x[n-1]$$
Let's observe this in practice.
import numpy, scipy, scipy.signal
b = [0, 1]
a = [1, 0]
w, h = scipy.signal.freqz(b, a)
b
and a
are the numerator and denominator coefficients of the filter's transfer function ([3]) in terms of z-1, and are common arguments for filter-related functions in scipy (e.g. freqz, lfilter):
Let's see some plots ([4]) to describe the behavior of the unit delay above (i.e. a first-order all-pass filter with λ = 0):
import matplotlib.pyplot as plt
fig1, ax11 = plt.subplots(figsize=(10, 7))
plt.title('frequency response of unit delay')
plt.plot(w/max(w), 20 * numpy.log10(abs(h)), 'b')
plt.ylim(-1, 1)
plt.ylabel('amplitude (dB)', color='b')
plt.xlabel(r'normalized frequency (x$\pi$rad/sample)')
ax11.grid()
ax21 = ax11.twinx()
angles = numpy.unwrap(numpy.angle(h))
plt.plot(w/max(w), angles, 'g')
plt.ylabel('phase (radians)', color='g')
plt.axis('tight')
x = numpy.sin(numpy.linspace(-numpy.pi, numpy.pi, 20))
y1 = scipy.signal.lfilter(b, a, x)
y2 = numpy.append([0], x[:-1])
samples = numpy.arange(max(max(len(x), len(y1)), len(y2)))
fig2, ax2 = plt.subplots(figsize=(10, 7))
plt.title(r'y[n] = $z^{-1}$x[n]')
plt.plot(samples, x, 'b', label='x[n]')
plt.plot(samples, y1, 'g', linestyle='--', alpha=0.8, label='y[n]')
plt.plot(samples, y2, 'r', linestyle=':', alpha=0.8, label='x[n-1]')
plt.xlabel('n (samples)')
plt.ylabel('amplitude', color='g')
ax2.grid()
ax2.legend(loc='upper right')
fig3, ax3 = plt.subplots(figsize=(10, 7))
plt.title('impulse and step response of unit delay')
l = 5
x_axis = numpy.arange(l)
impulse = numpy.zeros(l); impulse[0] = 1.0
impulse_response = scipy.signal.lfilter(b, a, impulse)
plt.plot(x_axis, impulse_response, color='b', alpha=0.9)
plt.ylabel('impulse response amplitude', color='b')
plt.xlabel('n (samples)')
ax4 = ax3.twinx()
step_response = numpy.cumsum(impulse_response)
plt.plot(x_axis, step_response, color='r', linestyle=':', alpha=0.9)
plt.ylabel('step response amplitude', color='r')
ax3.grid()
plt.axis('tight')
plt.show()
The flat frequency response is expected - an all-pass filter passes all frequencies equally. The phase response drops to -pi (-180°). What does that mean? Let's go back to the term mentioned earlier - unit delay, i.e.:
$$y[n] = D(z)x[n] \implies y[n] = x[n-1]$$Given that the normalized Nyquist frequency is π radians/sample, and the above graph is in terms of normalized frequency, a delay of 1 sample, i.e. -1 sample, is equivalent to a -pi radian phase shift.
λ is also known as the warping factor ([5]), limited to |λ| < 1 for stability ([6]):
$$-1 < \lambda < 1 \implies \left|\lambda\right| < 1$$Positive values of λ enhance the resolution (equalization) at low frequencies while negative values of λ enhance the resolution at high frequencies ([7])
Let's create the frequency, step, and impulse response plots again, with a varying lambda.
First, we should derive the new b
and a
arrays:
warp_factors = numpy.linspace(-0.99, 0.99, 5)
fig1, ax11 = plt.subplots(figsize=(10, 7))
ax11.grid()
plt.title(r'frequency response, varied $\lambda$')
plt.ylim(-1, 1)
plt.ylabel('amplitude (dB)', color='C0')
plt.xlabel(r'normalized frequency (x$\pi$rad/sample)')
for i, wf in enumerate(warp_factors):
w, h = scipy.signal.freqz([-wf, 1.0], [1.0, -wf])
ax11.plot(w/max(w), 20 * numpy.log10(abs(h)), 'C{0}'.format(i), label=wf)
ax21 = ax11.twinx()
plt.ylabel('phase (radians)', color='g')
for i, wf in enumerate(warp_factors):
w, h = scipy.signal.freqz([-wf, 1.0], [1.0, -wf])
angles = numpy.unwrap(numpy.angle(h))
ax21.plot(w/max(w), angles, 'C{0}'.format(i), label=wf)
ax11.legend(loc='upper right')
x = numpy.sin(numpy.linspace(-numpy.pi, numpy.pi, 20))
samples = numpy.arange(len(x))
fig2, ax2 = plt.subplots(figsize=(10, 7))
plt.title(r'y[n] = D(z)x[n], varied $\lambda$')
plt.plot(samples, x, 'b', label='x[n]')
plt.xlabel('n (samples)')
plt.ylabel('amplitude', color='g')
for i, wf in enumerate(warp_factors):
y = scipy.signal.lfilter([-wf, 1.0], [1.0, -wf], x)
plt.plot(samples, y, 'C{0}'.format(i), linestyle='--', alpha=0.6, label=r'y[n], $\lambda$={0}'.format(wf))
ax2.grid()
plt.legend(loc='upper right')
fig3, ax3 = plt.subplots(figsize=(10, 7))
plt.title(r'impulse and step response, varied $\lambda$')
l = 5
x_axis = numpy.arange(l)
impulse = numpy.zeros(l); impulse[0] = 1.0
plt.xlabel('n (samples)')
plt.ylabel('impulse response amplitude', color='b')
for i, wf in enumerate(warp_factors):
impulse_response = scipy.signal.lfilter([-wf, 1.0], [1.0, -wf], impulse)
plt.plot(x_axis, impulse_response, label='impulse, {0}'.format(wf), color='C{0}'.format(i), alpha=0.9)
plt.legend(loc='lower left')
ax4 = ax3.twinx()
plt.ylabel('step response amplitude', color='r')
for i, wf in enumerate(warp_factors):
impulse_response = scipy.signal.lfilter([-wf, 1.0], [1.0, -wf], impulse)
step_response = numpy.cumsum(impulse_response)
plt.plot(x_axis, step_response, label='step, {0}'.format(wf), color='C{0}'.format(i), linestyle=':', alpha=0.9)
ax3.grid()
plt.legend(loc='upper right')
plt.axis('tight')
plt.show()
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SciPy documentation, "scipy.signal.freqz," https://docs.scipy.org/doc/scipy/reference/generated/scipy.signal.freqz.html
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